Akron-Canton Airport Mini Guide
A rental car at Akron Canton Airport will take you conveniently around the main sights of the city. There is plenty to see there but with a hire car in Akron you will also be able to leave the city and explore further afield, perhaps to the Great Lakes in the north or nearby Cleveland, an hour away by car.
With internal flights, Akron is easily reached from America’s major airports. Flights arrive daily from
Boston,
Chicago,
Washington,
New York and
Philadelphia and many of these airports can be accessed by direct flights from Europe including the
UK.
Cleveland Hopkins airport, an hour away, offers even more routes from mainland airports where you can also collect a rental vehicle from.
Current Rental Rates in Akron-Canton Airport
Kia Rio
5 Adults, 4 Doors
From 73.59 EUR/day
7 Days rental at 515.18 EUR from 24/07/2023
Kia Soul
5 Adults, 4 Doors
From 74.26 EUR/day
7 Days rental at 519.84 EUR from 24/07/2023
Toyota Corolla
5 Adults, 4 Doors
From 74.93 EUR/day
7 Days rental at 524.51 EUR from 24/07/2023
Volkswagen Passat
5 Adults, 4 Doors
From 74.93 EUR/day
7 Days rental at 524.51 EUR from 24/07/2023
Kia Rio
5 Adults, 4 Doors
From 75.93 EUR/day
7 Days rental at 531.57 EUR from 24/07/2023
Toyota Camry
5 Adults, 4 Doors
From 76.09 EUR/day
7 Days rental at 532.68 EUR from 24/07/2023
Volkswagen Jetta
5 Adults, 4 Doors
From 76.09 EUR/day
7 Days rental at 532.68 EUR from 24/07/2023
Kia Soul
5 Adults, 4 Doors
From 76.56 EUR/day
7 Days rental at 535.94 EUR from 24/07/2023
Toyota Corolla
5 Adults, 4 Doors
From 76.56 EUR/day
7 Days rental at 535.94 EUR from 24/07/2023
Useful to know about Akron-Canton Airport
- Akron was the original home of Quaker Oats.
- The Goodyear tyre company began in Akron.
- It was also known as America’s rubber capital before many of the rubber factories closed.
- The abolitionist campaigner, John Brown, lived and worked in Akron.
- 1.65m passengers used the airport last year - a record
Popular car hire destinations in Akron-Canton Airport
Best car rental companies in Akron-Canton Airport
8.5
No.1: ALAMO,
based on 4541 reviews
24 min (average wait time)
8.3
No.2: ENTERPRISE,
based on 1886 reviews
20 min (average wait time)
8.1
No.3: NATIONAL,
based on 372 reviews
23 min (average wait time)
Akron-Canton Airport car hire information
-
€ 515.13
Average price:
(per week)
-
€ 73.59
Best Price:
Per Week
Average prices per day in Akron-Canton Airport
Item | Percent |
---|
January | € 75 |
---|
February | € 71 |
---|
March | € 73 |
---|
April | € 69 |
---|
May | € 68 |
---|
June | € 71 |
---|
July | € 77 |
---|
August | € 62 |
---|
September | € 62 |
---|
October | € 61 |
---|
November | € 62 |
---|
December | € 76 |
---|
Item | Percent |
---|
January | € 79 |
---|
February | € 74 |
---|
March | € 71 |
---|
April | € 69 |
---|
May | € 69 |
---|
June | € 72 |
---|
July | € 77 |
---|
August | € 65 |
---|
September | € 65 |
---|
October | € 64 |
---|
November | € 62 |
---|
December | € 75 |
---|
Item | Percent |
---|
January | € 139 |
---|
February | € 123 |
---|
March | € 112 |
---|
April | € 105 |
---|
May | € 108 |
---|
June | € 112 |
---|
July | € 118 |
---|
August | € 118 |
---|
September | € 112 |
---|
October | € 114 |
---|
November | € 121 |
---|
December | € 129 |
---|
Item | Percent |
---|
January | € 89 |
---|
February | € 83 |
---|
March | € 79 |
---|
April | € 74 |
---|
May | € 76 |
---|
June | € 80 |
---|
July | € 90 |
---|
August | € 79 |
---|
September | € 79 |
---|
October | € 79 |
---|
November | € 78 |
---|
December | € 95 |
---|
Item | Percent |
---|
January | € 112 |
---|
February | € 108 |
---|
March | € 94 |
---|
April | € 113 |
---|
May | € 114 |
---|
June | € 120 |
---|
July | € 154 |
---|
August | € 163 |
---|
September | € 151 |
---|
October | € 151 |
---|
November | € 164 |
---|
December | € 158 |
---|
Item | Percent |
---|
January | |
---|
February | |
---|
March | |
---|
April | € 42 |
---|
May | € 41 |
---|
June | € 44 |
---|
July | € 56 |
---|
August | € 38 |
---|
September | € 38 |
---|
October | € 36 |
---|
November | |
---|
December | |
---|
Item | Percent |
---|
January | € 93 |
---|
February | € 87 |
---|
March | € 83 |
---|
April | € 79 |
---|
May | € 78 |
---|
June | € 84 |
---|
July | € 93 |
---|
August | € 84 |
---|
September | € 85 |
---|
October | € 86 |
---|
November | € 84 |
---|
December | € 101 |
---|
Item | Percent |
---|
January | € 62 |
---|
February | € 56 |
---|
March | € 59 |
---|
April | € 116 |
---|
May | € 104 |
---|
June | € 103 |
---|
July | € 92 |
---|
August | € 72 |
---|
September | € 58 |
---|
October | € 60 |
---|
November | € 58 |
---|
December | € 51 |
---|
*average daily rates based on 7 day rental, search for today's best prices
Page_Load: CT_ID:3670 NodeID:25752 pvCT_ID:3670 NodeID:25752 DECLARE @CountryKeyword varchar(200), @CountryCode varchar(50),@DocumentPageTitle varchar(200), @DocumentPageDescription varchar(2000),@CT_ID int SELECT @DocumentPageTitle = DocumentPageTitle,@DocumentPageDescription = DocumentPageDescription from CMS_Document where DocumentNodeID =25752 SELECT Top 1 @CountryKeyword = CountryKeyword, @CountryCode = CountryCode from CONTENT_MenuItem where BookingEngineLocationID=3670 SELECT Top 1 @CT_ID = BookingEngineLocationID from CONTENT_MenuItem where BookingEngineLocationID=3670 Declare @TotalReviews varchar(200), @higest_rating float, @cheapest_price float, @CheapestVendor varchar(200),@expensive_price float, @offercount int; SET @TotalReviews = (select SUM(TotalAgent) as TotalReviews from[cartrawler_v2].[dbo].Review R where R.CartrawlerCode = @CT_ID and RecordDateTimeDt = (select MAX(RecordDateTimeDt) from[cartrawler_v2].[dbo].Review R where R.CartrawlerCode = @CT_ID)) SET @higest_rating = ( SELECT TOP 1 X.higest_rate * 2 as higest_rate FROM ( SELECT VendorName,CAST(overall AS decimal(5, 1)) AS higest_rate, CartrawlerCode FROM[cartrawler_v2].[dbo].[Review] WHERE CartrawlerCode = @CT_ID AND overall IS NOT NULL GROUP BY VendorName, overall, CartrawlerCode ) X ORDER BY CartrawlerCode, CAST(X.higest_rate AS decimal(5, 1)) DESC) SET @cheapest_price = ( SELECT CONVERT(Numeric(19, 2), min(computeddailyrate)) best_price FROM[cartrawler_v2].[dbo].[LocationVehicleV3] where CartrawlerCode = @CT_ID and vehiclematrixcategory<>'' and vehiclematrixcategory is not null and vehiclematrixcategory<> 'NULL' and RecordDateTimeDt = (select MAX(RecordDateTimeDt) from [cartrawler_v2].[dbo].[LocationVehicleV3] where CartrawlerCode=@CT_ID)) SET @CheapestVendor = ( select TOP 1 VendorShortName FROM[cartrawler_v2].[dbo].[ExtLocationVehicleV1] WHERE CartrawlerCode = @CT_ID AND RecordDateTimeDt = (select MAX(RecordDateTimeDt) from[cartrawler_v2].[dbo].[ExtLocationVehicleV1] where CartrawlerCode = @CT_ID ) order by computeddailyrate ) SET @expensive_price = ( SELECT TOP 1 CONVERT(Numeric(19,2),X.ComputedDailyRate) as expensive_price FROM ( SELECT [Expr1], MAX(ComputedDailyRate) as ComputedDailyRate, CountryCode, RecordDateTime, CountryName FROM [cartrawler_v2].[dbo].[LocationVehicleV2] group by [Expr1], CountryCode, RecordDateTime, RecordDateTimeDt, CountryName, CartrawlerCode HAVING (CountryCode= @CountryCode or CountryName = @CountryCode) AND ISNULL([Expr1], '') <> '' and CartrawlerCode = @CT_ID and RecordDateTimeDt = (select MAX(RecordDateTimeDt) from[cartrawler_v2].[dbo].[LocationVehicleV2] where(CountryCode= @CountryCode or CountryName = @CountryCode) and CartrawlerCode = @CT_ID) ) X ORDER BY X.ComputedDailyRate desc ) SET @offercount = (SELECT FLOOR(RAND() *(100-5+1))+5) SELECT @TotalReviews as TotalReviews, ratingavailable = CASE when @higest_rating is not null then @TotalReviews ELSE 0 END , higest_rating = CASE when @higest_rating is not null then @higest_rating ELSE 0 END , @cheapest_price as cheapest_price,@CheapestVendor as CheapestVendor, @expensive_price as expensive_price, @offercount as offercount,@DocumentPageTitle as DocumentPageTitle,@DocumentPageDescription as DocumentPageDescription
FAQs - How can we help?
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