Palanga Car Rental Mini Guide
Palanga is a popular tourist resort located in Lithuania. It is a coastal town that has eighteen kilometres of sandy beaches that line the shore of the Baltic. The summer is the busiest months for car hire in Palanga where the population swells from its normal 17,000. Therefore, we advise pre-booking your car rental online at least 4 weeks in advance to make sure you receive the vehicle you require at the absolute best price.
Palanga is served by Palanga international airport and operates domestic and some European flights including
London in the
UK and
Copenhagen in
Denmark. If you are flying into the airport a pre-booking rental car can be collected directly from the arrival’s hall with Rhino, you will just need to fill out the final paperwork and will soon be on your way to see what this fantastic city has to offer.
Current Rental Rates in Palanga
Volkswagen Polo
5 Adults, 5 Doors
From 79.36 EUR/day
7 Days rental at 555.55 EUR from 24/07/2023
Fiat 500
4 Adults, 3 Doors
From 79.36 EUR/day
7 Days rental at 555.55 EUR from 24/07/2023
Smart Forfour
4 Adults, 5 Doors
From 79.36 EUR/day
7 Days rental at 555.55 EUR from 24/07/2023
Toyota Yaris
5 Adults, 3 Doors
From 79.36 EUR/day
7 Days rental at 555.55 EUR from 24/07/2023
Smart Forfour
4 Adults, 5 Doors
From 82.22 EUR/day
7 Days rental at 575.55 EUR from 24/07/2023
Toyota Yaris
5 Adults, 3 Doors
From 82.22 EUR/day
7 Days rental at 575.55 EUR from 24/07/2023
Fiat 500
4 Adults, 3 Doors
From 82.22 EUR/day
7 Days rental at 575.55 EUR from 24/07/2023
Volkswagen Polo
5 Adults, 5 Doors
From 82.22 EUR/day
7 Days rental at 575.55 EUR from 24/07/2023
Volkswagen Golf
5 Adults, 5 Doors
From 107.52 EUR/day
7 Days rental at 752.67 EUR from 24/07/2023
Useful to know about Palanga
- Palanga is the 3rd biggest city in Lithuania behind Kaunas and Vilnius respectively.
- It’s also the country’s leading beach resort.
- The first people lived here over five thousand years ago.
- It was a key town on the amber route.
- Its beaches are 18km long.
Popular car hire destinations in Palanga
Best car rental companies in Palanga
7.1
No.1: CARSRENT,
based on 350 reviews
14 min (average wait time)
7.0
No.3: CARSRENT,
based on 350 reviews
17 min (average wait time)
7.0
No.2: CARSRENT,
based on 350 reviews
18 min (average wait time)
Palanga car hire information
-
€ 555.52
Average price:
(per week)
-
€ 79.36
Best Price:
Per Week
Average prices per day in Palanga
System.ArgumentOutOfRangeException: Index was out of range. Must be non-negative and less than the size of the collection.
Parameter name: index
at System.ThrowHelper.ThrowArgumentOutOfRangeException(ExceptionArgument argument, ExceptionResource resource)
at System.Collections.Generic.List`1.RemoveAt(Int32 index)
at CMSWebParts_MyWebParts_ChartCityAmchartsV1.generateGraph(String pvNodeID, String pvChartTitle)
at CMSWebParts_MyWebParts_ChartCityAmchartsV1.Page_Load(Object sender, EventArgs e)
Item | Percent |
---|
January | € 170 |
---|
February | € 162 |
---|
March | € 128 |
---|
April | € 101 |
---|
May | € 99 |
---|
June | € 98 |
---|
July | € 126 |
---|
August | € 166 |
---|
November | € 172 |
---|
December | € 176 |
---|
Item | Percent |
---|
January | € 142 |
---|
February | € 134 |
---|
March | € 120 |
---|
April | € 98 |
---|
May | € 92 |
---|
June | € 75 |
---|
July | € 97 |
---|
August | € 131 |
---|
November | € 140 |
---|
December | € 146 |
---|
Item | Percent |
---|
January | |
---|
February | |
---|
March | |
---|
April | € 43 |
---|
May | € 47 |
---|
June | € 71 |
---|
July | |
---|
August | |
---|
November | |
---|
December | |
---|
Item | Percent |
---|
January | € 328 |
---|
February | € 332 |
---|
March | € 327 |
---|
April | € 213 |
---|
May | € 249 |
---|
June | € 205 |
---|
July | € 270 |
---|
August | |
---|
November | € 356 |
---|
December | € 356 |
---|
Item | Percent |
---|
January | € 121 |
---|
February | € 109 |
---|
March | € 105 |
---|
April | € 100 |
---|
May | € 92 |
---|
June | € 74 |
---|
July | € 87 |
---|
August | € 118 |
---|
November | € 113 |
---|
December | € 121 |
---|
Item | Percent |
---|
January | € 264 |
---|
February | € 267 |
---|
March | € 263 |
---|
April | € 198 |
---|
May | € 221 |
---|
June | € 174 |
---|
July | € 203 |
---|
August | |
---|
November | € 286 |
---|
December | € 286 |
---|
Item | Percent |
---|
January | € 210 |
---|
February | € 212 |
---|
March | € 126 |
---|
April | € 111 |
---|
May | € 101 |
---|
June | € 121 |
---|
July | € 155 |
---|
August | € 187 |
---|
November | € 227 |
---|
December | € 227 |
---|
*average daily rates based on 7 day rental, search for today's best prices
Page_Load: CT_ID:161284 NodeID:10370 pvCT_ID:161284 NodeID:10370 DECLARE @CountryKeyword varchar(200), @CountryCode varchar(50),@DocumentPageTitle varchar(200), @DocumentPageDescription varchar(2000),@CT_ID int SELECT @DocumentPageTitle = DocumentPageTitle,@DocumentPageDescription = DocumentPageDescription from CMS_Document where DocumentNodeID =10370 SELECT Top 1 @CountryKeyword = CountryKeyword, @CountryCode = CountryCode from CONTENT_MenuItem where BookingEngineLocationID=161284 SELECT Top 1 @CT_ID = BookingEngineLocationID from CONTENT_MenuItem where BookingEngineLocationID=161284 Declare @TotalReviews varchar(200), @higest_rating float, @cheapest_price float, @CheapestVendor varchar(200),@expensive_price float, @offercount int; SET @TotalReviews = (select SUM(TotalAgent) as TotalReviews from[cartrawler_v2].[dbo].Review R where R.CartrawlerCode = @CT_ID and RecordDateTimeDt = (select MAX(RecordDateTimeDt) from[cartrawler_v2].[dbo].Review R where R.CartrawlerCode = @CT_ID)) SET @higest_rating = ( SELECT TOP 1 X.higest_rate * 2 as higest_rate FROM ( SELECT VendorName,CAST(overall AS decimal(5, 1)) AS higest_rate, CartrawlerCode FROM[cartrawler_v2].[dbo].[Review] WHERE CartrawlerCode = @CT_ID AND overall IS NOT NULL GROUP BY VendorName, overall, CartrawlerCode ) X ORDER BY CartrawlerCode, CAST(X.higest_rate AS decimal(5, 1)) DESC) SET @cheapest_price = ( SELECT CONVERT(Numeric(19, 2), min(computeddailyrate)) best_price FROM[cartrawler_v2].[dbo].[LocationVehicleV3] where CartrawlerCode = @CT_ID and vehiclematrixcategory<>'' and vehiclematrixcategory is not null and vehiclematrixcategory<> 'NULL' and RecordDateTimeDt = (select MAX(RecordDateTimeDt) from [cartrawler_v2].[dbo].[LocationVehicleV3] where CartrawlerCode=@CT_ID)) SET @CheapestVendor = ( select TOP 1 VendorShortName FROM[cartrawler_v2].[dbo].[ExtLocationVehicleV1] WHERE CartrawlerCode = @CT_ID AND RecordDateTimeDt = (select MAX(RecordDateTimeDt) from[cartrawler_v2].[dbo].[ExtLocationVehicleV1] where CartrawlerCode = @CT_ID ) order by computeddailyrate ) SET @expensive_price = ( SELECT TOP 1 CONVERT(Numeric(19,2),X.ComputedDailyRate) as expensive_price FROM ( SELECT [Expr1], MAX(ComputedDailyRate) as ComputedDailyRate, CountryCode, RecordDateTime, CountryName FROM [cartrawler_v2].[dbo].[LocationVehicleV2] group by [Expr1], CountryCode, RecordDateTime, RecordDateTimeDt, CountryName, CartrawlerCode HAVING (CountryCode= @CountryCode or CountryName = @CountryCode) AND ISNULL([Expr1], '') <> '' and CartrawlerCode = @CT_ID and RecordDateTimeDt = (select MAX(RecordDateTimeDt) from[cartrawler_v2].[dbo].[LocationVehicleV2] where(CountryCode= @CountryCode or CountryName = @CountryCode) and CartrawlerCode = @CT_ID) ) X ORDER BY X.ComputedDailyRate desc ) SET @offercount = (SELECT FLOOR(RAND() *(100-5+1))+5) SELECT @TotalReviews as TotalReviews, ratingavailable = CASE when @higest_rating is not null then @TotalReviews ELSE 0 END , higest_rating = CASE when @higest_rating is not null then @higest_rating ELSE 0 END , @cheapest_price as cheapest_price,@CheapestVendor as CheapestVendor, @expensive_price as expensive_price, @offercount as offercount,@DocumentPageTitle as DocumentPageTitle,@DocumentPageDescription as DocumentPageDescription
FAQs - How can we help?
There are always some points on which you are not sure when hiring a car, so we have done our best to answer the frequently asked questions. Just click this link and you will find the questions are sorted by category for easy navigation.